There is. Just encode the index of permutation used to scramble the otherwise sorted list. For 12 words you need to store 12! = ~32 bits so 3 words should be enough.Repetitions make this more difficult, though.On Thu 7. 7. 2022 at 19:41, Bram Cohen via bitcoin-dev <bitcoin-dev@lists.linuxfoundation.org> wrote:On Thu, Jul 7, 2022 at 7:43 AM Anton Shevchenko via bitcoin-dev <bitcoin-dev@lists.linuxfoundation.org> wrote:I made a python implementation for a different mnemonic encoding. The encoding requires user to remember words but not the order of those words.The code is open (MIT license) at https://github.com/sancoder/noomnemThanks Anton. There's an interesting mathematical question of whether it's possible to make a code like this which always uses the BIP-39 words for the same key as part of its encoding, basically adding a few words as error correction in case the order is lost or confused. If the BIP-39 contains a duplicate you can add an extra word._______________________________________________bitcoin-dev mailing list--Best Regards / S pozdravom,Pavol "stick" RusnakCo-Founder, SatoshiLabs