Good morning Thomas,

> So I think the question to ask would be "why can't we just make sure it's not 64?"

If we accept a 60-byte tx, then SHA-256 will pad it to 64 bytes, and it may still be possible to mount CVE-2017-12842 attack with 32-bits of work.
Of course some other details will be changed from the standard SHA-256 in mounting this attack, but from my poor understanding it seems safer to just avoid the area around length 64.

It *might* be safe to accept 65-byte or larger (but do not believe me, I only play a cryptographer on the Internet), but that does not help your specific application, which uses 60 byte tx.

Regards,
ZmnSCPxj

>
> On Sat, May 23, 2020 at 11:24 AM Greg Sanders <gsanders87@gmail.com> wrote:
>
> > AFAIU the number was picked to protect against CVE-2017-12842 covertly. See: https://github.com/bitcoin/bitcoin/pull/16885 which updated the text to explicitly mention this fact.
> >
> > On Sat, May 23, 2020 at 11:20 AM Thomas Voegtlin via bitcoin-dev <bitcoin-dev@lists.linuxfoundation.org> wrote:
> >
> > > Hello list,
> > >
> > > I have been trying to CPFP a transaction using OP_RETURN, because the
> > > remaining output value would have been lower than the dust threshold.
> > >
> > > The scriptPubkey of the output was OP_RETURN + OP_0, and there was a
> > > single p2wsh input.
> > >
> > > The result is a 60 bytes transaction (without witness), that gets
> > > rejected because it is lower than MIN_STANDARD_TX_NONWITNESS_SIZE, which
> > > is equal to 82 bytes.
> > >
> > > Why is that value so high? Would it make sense to lower it to 60?
> > >
> > > Thomas
> > > _______________________________________________
> > > bitcoin-dev mailing list
> > > bitcoin-dev@lists.linuxfoundation.org
> > > https://lists.linuxfoundation.org/mailman/listinfo/bitcoin-dev
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